三相电功率计算器

免费三相电功率计算器,输入值直接在您的设备上计算。

Technical reference: Schneider Electric power and power-factor guidance. Results assume sinusoidal voltage/current and a balanced three-phase load. Measure phase imbalance and harmonics separately.

How to use this calculator

  1. Choose what you know: voltage & current or voltage & power (kW).
  2. Enter the line-to-line voltage (e.g. 400 V) — the voltage measured between any two phases.
  3. Enter the line current in amps, or the real power in kW.
  4. Enter the power factor (0–1): about 0.9 for motors at full load, 1.0 for purely resistive loads.
  5. Read the current, real power (kW), apparent power (kVA) and reactive power (kVAR).

Three-phase power formulas

For a balanced three-phase load using the line-to-line voltage VL:

S (kVA) = √3 × VL × I / 1000
P (kW) = √3 × VL × I × PF / 1000
I (A) = P × 1000 / (√3 × VL × PF)

The same line-quantity formula works for both star (wye) and delta connections, because √3 already accounts for the phase-to-line relationship. Using phase quantities instead: P = 3 × Vphase × Iphase × PF.

Symbols and units

SymbolMeaningUnit
VLLine-to-line voltagevolts (V)
ILine currentamps (A)
PReal (active) powerkilowatts (kW)
SApparent powerkilovolt-amps (kVA)
QReactive powerkVAR
PFPower factor = P / S0 to 1

Quick reference: amps to kW at 400 V (three-phase)

How many kW a balanced three-phase load draws at 400 V:

CurrentkW at PF 0.8kW at PF 1.0
10 A5.56.9
16 A8.911.1
20 A11.113.9
25 A13.917.3
32 A17.722.2
40 A22.227.7
50 A27.734.6
63 A34.943.6
80 A44.355.4
100 A55.469.3
125 A69.386.6
160 A88.7110.9

For 415 V multiply by 1.04; for 380 V multiply by 0.95.

常见问题

What is the difference between kW and kVA?
kW is real power (the part that does useful work); kVA is apparent power (the total the supply must deliver). They are linked by the power factor: kW = kVA × PF, and are equal only when PF = 1.
How many kW is 100 A at 400 V three-phase?
At PF 1.0 it is √3 × 400 × 100 ÷ 1000 ≈ 69.3 kW; at PF 0.8 it is about 55.4 kW.
What power factor should I use?
About 0.85–0.9 for induction motors at full load, lower for lightly loaded motors, and 1.0 for purely resistive loads such as heaters.
Do I use line or phase voltage?
Use the line-to-line voltage (e.g. 400 V) with the √3 formulas above. The √3 factor already converts between phase and line values for a balanced load.

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